leetCode/sql/超过经理收入的员工.sql

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/**
Employee 表包含所有员工,他们的经理也属于员工。每个员工都有一个 Id此外还有一列对应员工的经理的 Id。
```
+----+-------+--------+-----------+
| Id | Name | Salary | ManagerId |
+----+-------+--------+-----------+
| 1 | Joe | 70000 | 3 |
| 2 | Henry | 80000 | 4 |
| 3 | Sam | 60000 | NULL |
| 4 | Max | 90000 | NULL |
+----+-------+--------+-----------+
```
给定 Employee 表,编写一个 SQL 查询该查询可以获取收入超过他们经理的员工的姓名。在上面的表格中Joe 是唯一一个收入
超过他的经理的员工。
```
+----------+
| Employee |
+----------+
| Joe |
+----------+
```
**/
select a.Name as Employee
from Employee a, (select Salary,Id from Employee) b
where a.ManagerId=b.Id and a.Salary > b.Salary